-3x+[5-2(x+1)]=

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Solution for -3x+[5-2(x+1)]= equation:


Simplifying
-3x + [5 + -2(x + 1)] = 0

Reorder the terms:
-3x + [5 + -2(1 + x)] = 0
-3x + [5 + (1 * -2 + x * -2)] = 0
-3x + [5 + (-2 + -2x)] = 0

Combine like terms: 5 + -2 = 3
-3x + [3 + -2x] = 0

Remove brackets around [3 + -2x]
-3x + 3 + -2x = 0

Reorder the terms:
3 + -3x + -2x = 0

Combine like terms: -3x + -2x = -5x
3 + -5x = 0

Solving
3 + -5x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -5x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5x = 0 + -3
-5x = 0 + -3

Combine like terms: 0 + -3 = -3
-5x = -3

Divide each side by '-5'.
x = 0.6

Simplifying
x = 0.6

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